ITH Poker Forum

[Da_Big_Fish]

The video is here:
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<a href="http://academy.fulltiltpoker.com/lessons/video/53/mathematical-shortcuts" target="_blank">http://academy.fulltiltpoker.com/lessons/video/53/mathematical-shortcuts</a>
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Basically, this gives you a percentage of how often your pair will be the best at the table.
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It goes like this:
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1. Count the number of pairs higher than your pair.
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2. Count the number of players left to act.
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3. Multiply the number of players and how many pairs are higher than yours
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4. Divide your answer in 3 by 2.
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Ex.
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You have JJ UTG. 9 handed table .
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Hands higher than JJ = 3
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Players left to act 8
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(3x8)/2 = 12
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So there is a 12% chance that your JJ is the best hand..
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Ex, 2
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88 in the cuttoff
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Pairs higher than 88 - 6
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players left - 3
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(3 x 6)/2 = 9
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So there is a 9% chance that your 88 is the best pair.
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My question is this seems to only apply to people after you not those behind you. If you get several limpers before it's your turn to act, wouldn't you take that into account in the calculation?
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In the last example, I am thinking well it's great that there is only a 9% chance that either the SB or BB has a better pair than me but what about the rest of those guys behind me. What does knowing that my pair is bigger than the SB and BB do for me if someone from UTG+2 has 99 or TT.