I'm working my way through the hand examples in Chapter 8, and have a question about Problem 8-6. (I'm only going to include what I think is the pertinent info, but if you'd like a summary of the entire problem, just let me know & I'll post it.)
In this problem, we are dealt 6:diamond 5:diamond and the flop comes:
6:spade 3:club 2:diamond
The turn is the 2:heart
At this point, I'm correct in thinking that I have two pair, sixes & deuces, right?
The river is the K:diamond
In his analysis of the hand after the river, Harrington says:
The King wasn't helpful, but it probably wasn't a disaster either. Players are much less likely to hang around with K x than with A x. However, you don't have anything more than you have represented from the beginning, top pair.
Did I miss something, or is there a typo somewhere? I did have two pair on the turn, didn't I? And I can use any 5 cards (it doesn't have to be the 5 highest cards, does it?) from the board and my hole cards to make the best hand, right? I know it seems like a silly question, but I just can't figure out where Harrington's coming from with this one and it's driving me crazy.
Thanks,
sleepy

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